MAY 4 2026: APP 2.0.0-beta44 has been released !
New improved internal memory controls should now work on all computers
May 1 2026: APP 2.0.0-beta43 has been released !
Improved internal memory controls (much more stable and faster on big datasets), fixed CPU image viewer, fixed Narrowband extraction demosaic algortihms.
Apr 29 2026 APP 2.0.0-beta42 has been released !
New improved Normalization engine, Fixed random crashes in integration, fixed RGB Combine & Calibrate Star Colors, fixed Narrowband extraction algorithms, new development platform with performance gains, bug fixes in the tools, etc...
Apr 14 2026: Google Pay, Apple Pay & WeChat Pay added as payment options
Update on the 2.0.0 release & the full manual
We are getting close to the 2.0.0 stable release and the full manual. The manual will soon become available on the website and also in PDF format. Both versions will be identical and once released, will start to follow the APP release cycle and thus will stay up-to-date to the latest APP version.
Once 2.0.0 is released, the price for APP will increase. Owner's license holders will not need to pay an upgrade fee to use 2.0.0, neither do Renter's license holders.
In my humble understanding the 'Ha-OIII extract Ha' algorithm basically extracts the red channel from the OSC image. If this is true, I could use it to extract the Sulfur signal from an OSC image taken with an OIII/SII Filter like e.g. the Askar D2. But maybe I'm wrong and there is some hidden magic going on which makes this a bad idea. Please advice.
I'm fairly optimistic that I can use the 'Ha-OII extract OIII' algorithm to extract OIII from an OSC image taken with an OIII/SII filter. If not, I'm totally confused.Â
Thank you for your support!
Wolfgang
Ok, I found the related posts and I'm happy about the confirmation that it's possible to use the 'Ha-OIII extract Ha' algorithm to get the SII channel from the OIII/SII OSC data.
https://www.astropixelprocessor.com/community/tutorials-workflows/askar-colour-magic-filter-c1-c2-stacking-flow/#post-30580 is the most useful link in the chain of links you have to follow to find a definitive answer.
